首页游戏问答dnf手游代码106:如何在DNF手游中快速通关106副本?

dnf手游代码106:如何在DNF手游中快速通关106副本?

来源:游游猫下载网 编辑:手游零氪 发布时间:2026-01-23 13:04:35

importnumpyasnp

defdfs(maze,start,end):

stack=[start]

visited=set()

whilestack:

x,y=stack.pop()

if(x,y)==end:

returnTrue

visited.add((x,y))

fordx,dyin[(1,0),(1,0),(0,1),(0,1)]:

nx,ny=x+dx,y+dy

if0<= nx < len(maze) and 0 <= ny < len(maze[0]) and maze[nx][ny] == 0 and (nx, ny) not in visited:

stack.append((nx,ny))

returnFalse

importnumpyasnp

defavoid_traps(maze,traps):

path=

x,y=0,0

while(x,y)!=(len(maze)1,len(maze[0])1):

path.append((x,y))

next_moves=

fordx,dyin[(1,0),(1,0),(0,1),(0,1)]:

nx,ny=x+dx,y+dy

if0<= nx < len(maze) and 0 <= ny < len(maze[0]) and maze[nx][ny] == 0 and (nx, ny) not in traps:

next_moves.append((nx,ny))

ifnext_moves:

x,y=min(next_moves,key=lambdap:abs(p[0](len(maze)1))+abs(p(len(maze[0])1)))

else:

returnNone

returnpath

defkill_boss(boss_health,team_damage):

whileboss_health>0:

fordamageinteam_damage:

boss_health=damage

ifboss_health<= 0:

returnTrue

returnFalse

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